Let f(x) be a C3 function on some open set I and x0∈I, then for any x∈I, we have
f(x)=f(x0)+f′(x0)(x−x0)+2!f′′(x0)(x−x0)2+2!1∫x0x(x−τ)2f′′′(τ)dτ
f(x,y)=+++f(x0,y0)[fx(x0,y0)(x−x0)+fy(x0,y0)(y−y0)]2!1[fxx(x−x0)2+2fxy(x−x0)(y−y0)+fyy(y−y0)2] Remainder