Min-Max 容斥算法
Min-Max 容斥可以在已知一者的情况下求出另外一者,如
max(a,b)=a+b−min(a,b)max(a,b,c)=a+b+c−min(a,b)−min(a,c)−min(b,c)+min(a,b,c)我们把这个式子推广到 n 个变量的情况的话,就有(令 S={a1,a2,…,an})
min(S)=T⊆S∑(−1)∣T∣−1max(T)max(S)=T⊆S∑(−1)∣T∣−1min(T)
mink(S)=T⊆S∑(−1)∣T∣−k(k−1∣T∣−1)max(T)maxk(S)=T⊆S∑(−1)∣T∣−k(k−1∣T∣−1)min(T)
证明